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Question

8.7g of pure MnO2 is heated with an excess of HCl and the gas evolved is passed into a solution of KI. Calculate the weight of the iodine librated (Mn=55,Cl=35.5.I=127)

A
7.77g
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B
16.41g
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C
12.70g
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D
25.4g
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Solution

The correct option is D 25.4g
The chemical equation for the reaction between MnO2 and HCl can be written as:
MnO2+4HClCl2+MnCl2+2H2O
Now molecular weight of MnO2 = 87g
87g of MnO2 produces = 71g 0f Cl2
8.7g MnO2 produces = 7.1g 0f Cl2
Now chlorine gas reacts with KI as:
Cl2+2KII2+2KCl
71g of Cl2 liberates = 254g of I2
7.1g of Cl2 liberates = 25.4g of I2

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