Question

8+88+888+........=

• A. $\frac{80}{81}({10}^n-1)-\frac{8n}{9}$
  
• B. $\frac{10}{81}({10}^n-1)$
  
• C. $\frac{80}{81}({10}^n-1)+\frac{8n}{9}$
  
• D. None of these

Answer 1

The correct option is A

$\frac{80}{81}({10}^n-1)-\frac{8n}{9}$

$S=8+88+888+.....=\frac{8}{9}[9+99+999+......]\frac{8}{9}\left[\right(10-1)+({10}^2-1)+({10}^3-1)+.....]\frac{8}{9}\left[\right(10+{10}^2+{10}^3+......)-(1+1+1+......\left)\right]\frac{8}{9}[10.\frac{{10}^n-1}{10-1}-n]$
$=\frac{8}{81}[{10}^{n+1}-9n-10]$
$=\frac{80}{81}({10}^n-1)-\frac{8n}{9}$