8. An electric heater of power 220 W is connected to 220 V supply.Calculate the current, it's resistance and cost of using it for 5 hours daily for 30 days at the rate of Rs.240 per unit.

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Solution

Dear Student ,

$W e k n o w t h a t, p o w e r = P = V I = 220 \Rightarrow 220 \times I = 220 \Rightarrow I = \frac{220}{220} = 1 A A g a i n, P = I^{2} R \Rightarrow R = \frac{P}{I^{2}} = \frac{220}{1} = 220 Ω S o t h e t o t a l p o w e r c o n s u m e d f o r u \sin g d a i l y 5 h o u r s f o r 30 d a y s = 220 \times 5 \times 30 = 33000 W h = 33 K W h S o t h e \cos t o f e l e c t r i c i t y i s = 33 \times 240 = 7920 r u p e e s .$
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8. An electric heater of power 220 W is connected to 220 V supply.Calculate the current, it's resistance and cost of using it for 5 hours daily for 30 days at the rate of Rs.240 per unit.

Dear Student , We know that , power =P =VI=220⇒220×I=220⇒I=220220=1AAgain , P=I2R⇒R=PI2=2201=220ΩSo the total power consumed for using daily 5 hours for 30 days=220×5×30=33000Wh=33 KWhSo the cost of electricity is=33×240=7920 rupees. Regards