$8 g N a O H$ is dissolved in one litre of solution, the molarity of the solution is:

0.2 M

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0.4 M

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0.02 M

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0.8 M

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Solution

The correct option is A $0.2 M$
Given,
$8 g$ of $N a O H$ dissolved in one litre of solution.

Molar Mass $(N a O H) = 40$

Molarity $= \frac{n_{B}}{V (m L)} \times 1000$

$= \frac{8}{40} \times \frac{1000}{1000} = 0.2$

$∴$ M $= 0.2$ moles/litre

Hence, the correct option is $A$

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A scene in a fantasy chemistry lab.
Faraday was measuring the concentration of different solutes in different solutions. But he forgot the exact formula for Molarity, Molality and Normality. He decides to ask his colleagues.

Davy: ''Molarity is the number of moles of solute dissolved in 1 litre of solvent.''
Boyle: ''Molality is the number of moles of solute dissolved in 1 kg of solvent.''
Cavendish: ''Normality is the number of equivalents of solute dissolved in 1 litre of solution.''

Who do you think Faraday should believe? You can choose more than one.

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8 g NaOH is dissolved in one litre of solution, the molarity of the solution is:

The correct option is A 0.2 MGiven,8g of NaOH dissolved in one litre of solution.Molar Mass(NaOH)=40Molarity=nBV(mL)×1000=840×10001000=0.2∴ M=0.2 moles/litreHence, the correct option is A

$8 g N a O H$ is dissolved in one litre of solution, the molarity of the solution is:

The correct option is A $0.2 M$
Given,
$8 g$ of $N a O H$ dissolved in one litre of solution.

Molar Mass $(N a O H) = 40$

Molarity $= \frac{n_{B}}{V (m L)} \times 1000$

$= \frac{8}{40} \times \frac{1000}{1000} = 0.2$

$∴$ M $= 0.2$ moles/litre

Hence, the correct option is $A$