$8 g$ of $O_{2}$ has the same number of atoms as

$7 g C O$

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$14 g$ of $C O$

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$22 g$ of $C O_{2}$

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$44 g$ of $C O_{2}$

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Solution

The correct option is A
$7 g C O$

No of atoms = $\frac{W}{M} \times N \times a t o m i c i t y$

$8 g$ oxygen = $\frac{8}{32} \times N \times 2$ = $0.5 N$

$14 g C O$ = $\frac{7}{28} \times N \times 2$ = $0.5 N$

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$8 g$ of $O_{2}$ has the same number of atoms as ___ gm of CO

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