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Question

8 g of sulfur is burnt to form SO2 which is oxidized by Cl2 water. The solution is treated with BaCl2 solution. Moles of BaSO4 precipitated are:

A
1.0 mole
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B
0.5 mole
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C
0.75 mole
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D
0.25 mole
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Solution

The correct option is D 0.25 mole
The reactions for the processes are
S + O2 SO2

Moles of sulfur is 832 =0.25mole

SO2 + Cl2 +2H2O H2SO4 + 2HCl

H2SO4 + BaCl2 BaSO4 + 2HCl

Here, 0.25 moles of S will produce 0.25 moles of SO2 which is consumed in next reaction and gives 0.25 moles of H2SO4 which in the third reaction gives 0.25 moles of BaSO4. So, moles of BaSO4 precipitated is 0.25.
Hence, the correct option is D.

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