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Standard XII

Chemistry

Characteristics of Equilibrium Constant

8 moles of a ...

Question

$8$ moles of a gas $A B_{3}$ are introduced into a $1.0 d m^{3}$ vessel.
It dissociates as $2 A B_{3} ⇌ A_{2} (g) + 3 B_{2} (g)$
At equilibrium, $2$ moles of $A_{2}$ are found to be present. The equilibrium constant of the reaction is

2 m o l^{2} L^{- 2}

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3 m o l^{2} L^{- 2}

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27 m o l^{2} L^{- 2}

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36 m o l^{2} L^{- 2}

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Solution

The correct option is B $3 m o l^{2} L^{- 2}$
$2 {A B}_{2} ⇌ A_{2} (g) + 3 B_{2} (g)$
at t=0 $8 m o l$ $-$ $-$
at eqn, $2 (8 - 2) m o l$ $2 m o l$ $6 m o l$
$[{A B}_{2}] = 12 m o l L^{-} [A_{2}] = 2 m o l L^{- 1}$
$[B_{2}] = 6 m o l L^{- 1}$
equilibrium constant $K_{C} = \frac{[A_{2}] {[B_{2}]}^{3}}{[{A B}_{3}]}$
$= \frac{{(6)}^{3} \times 2}{{(12)}^{2}} = 3 {m o l}^{2} L^{- 2}$

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Similar questions

8

mole of a gas

{A B}_{3}

are introduced into a

1.0 {d m}^{3}

vessel. It dissociates as:

2 A B_{3} (g) ⇌ A_{2} (g) + 3 B_{2} (g)

at equilibrium,

2

mole of

A_{2}

are found to be present. The equilibrium constant of the reaction is:

Q. 8 mol of a gas

A B_{3}

are introduced into a 1.0

d m^{3}

vessel. It dissociates as

2 A B_{3} (g) ⇌ A_{2} (g) + 3 B_{2} (g)

At equilibrium, 2 mol of

A_{2}

is found to be present. The equilibrium constant for the reaction is :

Q. 8 moles of a gas

A B_{3}

attain equilibrium in a closed container of volume

1 {d m}^{3}

as,

2 A B_{3} ⇌ A_{2} (g) + 3 B_{2} (g)

If at equilibrium, 2 moles of

A_{2}

is present then, the equilibrium constant is :

Q. At a certain temperature (T), the equilibrium constant

(K_{c})

is 1 for the reaction

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

If 2 moles of

N_{2},

4 moles of

H_{2},

6 moles of

N H_{3}

and 3 moles of inert gas are introduced into a two litre rigid vessel at constant temperature T. It has been found that equilibrium concentration of

H_{2}

and

N H_{3}

are equal then what is the equilibrium concentration of

N_{2}

(in M)?

Q. Two moles of

N H_{3}

gas are introduced into a previously evacuated one litre vessel in which it partially dissociates at high temperature as

2 N H_{3} (g) ⇋ N_{2} (g) + 3 H_{2} (g)

. At equilibrium, one mole of

N H_{3} (g)

remain. The value of

K_{c}

is:

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8 moles of a gas AB3 are introduced into a 1.0 dm3 vessel.It dissociates as 2AB3⇌A2(g)+3B2(g)At equilibrium, 2 moles of A2 are found to be present. The equilibrium constant of the reaction is

The correct option is B 3 mol2L−2 2AB2⇌A2(g)+3B2(g)at t=0 8mol − −at eqn, 2(8−2)mol 2mol 6mol[AB2]=12molL−[A2]=2molL−1[B2]=6molL−1equilibrium constant KC=[A2][B2]3[AB3] =(6)3×2(12)2=3mol2L−2

$8$ moles of a gas $A B_{3}$ are introduced into a $1.0 d m^{3}$ vessel.
It dissociates as $2 A B_{3} ⇌ A_{2} (g) + 3 B_{2} (g)$
At equilibrium, $2$ moles of $A_{2}$ are found to be present. The equilibrium constant of the reaction is