Question

8 numbers between 6 and 33 such that the sequence is an AP are

• A. 6,9,12, ...,33
• B. 12,15,18,..,30
• C. 9,12,15,..30
• D. 9,11,13,..28

Answer 1

The correct option is C

9,12,15,..30

For finding n numbers between a and b such that the sequence is an AP we need to find common difference d= (b-a)/n+1

Then the numbers are a+d,a+2d,..., a+nd

In this case, a=6, b=33 n = 8

So, d=3.

Thus, the numbers are 9, 12, 15,..., 30.