Question

$8\%$ of the voters in an election did not cast their votes. In the election there were only two candidates. The winner by obtaining $48\%$ of the total votes defeated his contestant by $1100$ votes. The total number of the voters in the election was

• A. $21000$
• B. $23500$
• C. $22000$
• D. $27500$

Answer 1

The correct option is D $27500$

Per cent of votes cast $=100\%-8\%=92\%$
Winner got $48\%$ of the total votes.
$\Rightarrow$ Loser got $(92-48)\%$ i.e. $44\%$ of the total Votes.
Difference $=4\%$
Given, $4\%$ of total votes cast $=1100$
Total votes cast $=\frac{1100\times 100}{4}=27500$