Question

8 taps can fill a tank in 27 minutes with the same rate of flow.If three taps go out of order, how long will the remaining taps take to fill the tank?

Answer 1

$8$ taps can fill a tank in $27$ minutes.

So, $1$ tap can fill the same tank in time $=27\times 8=218$ minutes

$\therefore ,5$ remaining taps can fill the same tank $=\frac{125}{5}=25$ minutes

The remaining $5$ taps will take $25$ minutes to fill the same tank.