Question

8 taps having the same size, fill a tank in 27 minutes. If two taps go out of order, how long would the remaining taps take to fill the tank ?

Answer 1

8 taps can fill tank in = 27 minutes

1 tap can fill that tank in = 27 $\times$ 8 minutes (less tap, more time)

8 - 2 = 6 taps can fill that tank in

$=\frac{27\times 8}{6}minutes$ (more taps, less time)

$=36$ minutes.