Question

$8$ taps of the same size fill a tank in $27$ minutes. If two taps go out of order, how long would the remaining taps take to fill the tank?

• A. $86$ minutes
• B. $56$ minutes
• C. $66$ minutes
• D. $36$ minutes

Answer 1

The correct option is D $36$ minutes

Given that,

$8$ taps of the same size fill a tank in $27$ minutes.

So, $1$ tap can fill the tank in $8\times 27=216$ minutes

If two taps go out of order, then the remaining taps $=8-2=6$

Therefore, Time taken by $6$ taps to fill the tank $=\frac{216}{6}=36$ minutes.