Question 64 8 - 106-2 - 104-5 - 102-9 - 100-8020509

Name: EXEMP - Grade 07 - MATHEMATICS - Exponents & Powers - Q64
Uploaded: 2022-07-04T10:36:42+05:30
Description: True Taking LHS =(8 × 10^6)+(2 × 10^4)+(5 × 10^2)+(9 × 10^0) =(8 × 1000000) + (2 × 10000) +(5 × 100)+ (9 × 1) =8000000+2000+500+9 =8020509 = RHS Hence, LH ...

True Taking LHS =(8 × 10^6)+(2 × 10^4)+(5 × 10^2)+(9 × 10^0) =(8 × 1000000) + (2 × 10000) +(5 × 100)+ (9 × 1) =8000000+2000+500+9 =8020509 = RHS Hence, LH ...

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Standard VII

Mathematics

Expanding a Rational Number Using Powers

Question 64 8...

Question

Question 64

$8 \times 10^{6} + 2 \times 10^{4} + 5 \times 10^{2} + 9 \times 10^{0} = 8020509$

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Solution

True
Taking LHS
$= (8 \times 10^{6}) + (2 \times 10^{4}) + (5 \times 10^{2}) + (9 \times 10^{0}) = (8 \times 1000000) + (2 \times 10000) + (5 \times 100) + (9 \times 1) = 8000000 + 2000 + 500 + 9 = 8020509 = RHS Hence, LHS = RHS$

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Expanding a Rational Number Using Powers

Standard VII Mathematics

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Question 64 8×106+2×104+5×102+9×100=8020509

True Taking LHS =(8×106)+(2×104)+(5×102)+(9×100)=(8×1000000)+(2×10000)+(5×100)+(9×1)=8000000+2000+500+9=8020509=RHSHence, LHS = RHS

Question 64

$8 \times 10^{6} + 2 \times 10^{4} + 5 \times 10^{2} + 9 \times 10^{0} = 8020509$

True
Taking LHS
$= (8 \times 10^{6}) + (2 \times 10^{4}) + (5 \times 10^{2}) + (9 \times 10^{0}) = (8 \times 1000000) + (2 \times 10000) + (5 \times 100) + (9 \times 1) = 8000000 + 2000 + 500 + 9 = 8020509 = RHS Hence, LHS = RHS$