Question

8.·x,15 21 27 30 35

Answer 1

The given data is:

x i	15	21	27	30	35
f i	3	5	6	7	8

The cumulative frequency table is created as follows:

x i	f i	c.f.
15	3	3
21	5	3+5=8
27	6	8+6=14
30	7	14+7=21
35	8	21+8=29
	∑ i=1 n f i =29

N is odd. Therefore,

M= ( n+1 2 ) th

M= ( 29+1 2 ) th = ( 30 2 ) th = 15 th =30

Therefore, the median of the given data is 30.

Creating the following table to find mean deviation:

x i	f i	| x i −M |	f i | x i −M |
15	3	15	45
21	5	9	45
27	6	3	18
30	7	0	0
35	8	5	40
	∑ i=1 n f i =29		∑ i=1 n f i | x i −M | =148

M.D= ∑ i=1 n f i | x i −M | ∑ i=1 n f i M.D= 1 N ∑ i=1 n f i | x i −M |

M.D.= 148 29 =5.1

Therefore, the mean deviation of the given data is 5.1.