Question

80 g of water at 30${}^{0}C$ are poured a large block of ice at 0${}^{0}C$. The mass of ice that melts is

• A. 30 g
• B. 80 g
• C. 1600 g
• D. 150 g

Answer 1

The correct option is A 30 g

It is known that

Heat lost = Heat gain

$Q_L=Q_G$

If $m$ gm ice melts then

and we known heat loss/gain is given by $Q=m.c.\Delta \theta$

According to question:

$80\times 1\times (30-0)=m\times 80\Rightarrow m=30gm$