80 gm of water at 30- C are poured on a large block of ice at 0- C- The mass of ice that melts is

If m gm ice melts then Heat lost = Heat gain 80 × 1 × ( 30 0 ) = m × 80 ⇒ m = 30 gm ...

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Calorimetry

80 gm of wate...

Question

80 gm of water at $30^{\circ} C$ are poured on a large block of ice at $0^{\circ} C$ . The mass of ice that melts is

30 gm

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80 gm

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1600 gm

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150 gm

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80 gms of water at 30C is poured on a large block of ice at 0C the mass of the ice that melts is

^{0} C

^{0} C

80 gm of water at $30^{o} C$ are poured on a large block of ice at $0^{o} C$ . The mass of ice that melts is

80 g

30^{o} C

0^{o} C

80 g

30^{o} C

0^{\circ}

334 J / g

= 4.2 J g^{- 1} C^{o - 1}

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