80 gm of water at 30∘C are poured on a large block of ice at 0∘C. The mass of ice that melts is
30 gm
80 gm
1600 gm
150 gm
If m gm ice melts then
Heat lost = Heat gain
80×1×(30−0)=m×80⇒m=30gm
80 gms of water at 30C is poured on a large block of ice at 0C the mass of the ice that melts is