Question

$800c{m}^3$ of gas is collected at $650$ mm pressure. At what pressure would the volume of the gas reduce by $40\%$ of its original volume, temperature remaining constant?

Answer 1

According to Boyle's law $P_1{V}_1=P_2{V}_2$

$\Rightarrow P_1=650mm,V_1=800c{m}^3,$

$V_2=$Volume reduced by $40$%. Remaining volume is $60$% of its original volume$=\frac{800\times 60}{100}=480c{m}^3$.

$\Rightarrow P_2=\frac{650\times 800}{480}=1083mm$