$800$ g of a $40 %$ solution by weight was cooled. $100$ g of solute was precipitated. The percentage composition of remaining solution is :

31.4 %

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20.0 %

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23.0 %

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24 %

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Solution

The correct option is A $31.4 %$
$S o l u t e p r e s e n t i n 800 g s o l u t i o n = 800 \times \frac{40}{100}$ $= 320 g$
$S o l u t e p r e c i p i t a t e d = 100 g$
$S o l u t e l e f t = 220 g$
$∴ T o t a l w e i g h t o f s o l u t i o n = 800 - 100 = 700 g$
$700 g s o l u t i o n h a s s o l u t e = 220$
$100 g s o l u t i o n h a s s o l u t e = \frac{220}{700} \times 100 = 31.43$ %

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800 g of a 40% solution by weight was cooled. 100 g of solute was precipitated. The percentage composition of remaining solution is :

The correct option is A 31.4%Solutepresentin800gsolution=800×40100=320gSoluteprecipitated=100gSoluteleft=220g∴Totalweightofsolution=800−100=700g700gsolutionhassolute=220100gsolutionhassolute=220700×100=31.43%

$800$ g of a $40 %$ solution by weight was cooled. $100$ g of solute was precipitated. The percentage composition of remaining solution is :