Question

$8^2$ = __________ ( as a perfect cube)
and $2^2$ = _____________ ( as cube root)

• A. $4^3$, $\sqrt[3]{364}$
• B. $4^3$, $\sqrt[3]{38}$
• C. $4^3$, $\sqrt[3]{336}$
• D. $2^3$, $\sqrt[3]{316}$

Answer 1

The correct option is A $4^3$, $\sqrt[3]{364}$

$8^2$ = $8\times 8$ = 64
Now 64 can also be written as $4\times 4\times 4$ = 64 = $4^3$
$\therefore$ $8^2$ = $4^3$
$2^2$ = $2\times 2$ = 4
As seen above, 64 = $4^3$
$\therefore$ 4 = $\sqrt[3]{364}$
Hence, $2^2$ = $\sqrt[3]{364}$