Question

There are two charges +1uc and +5uc. what is the ratio of the force acting on them?

Answer 1

Step 1: Given

q₁=+1μC

q₂=+5μC

Let r is distance between them.

$F{21}^{}$ is force experienced on charge q₂ by q₁.

$F{12}^{}$ is force experienced on charge q₁ by q₂.

Step 2: Formula used

F=$\frac{1}{r{2}^{}}$ kq₁*q₂

Step 3: Finding the ratio of force between charges

$F{12}^{}$ =$\frac{1}{r{2}^{}}$ kq₁*q₂

$F{21}^{}$ =$\frac{1}{r{2}^{}}$ kq₁*q₂

The magnitude of both the force is the same.

$F{12}^{}$ =$F{21}^{}$ =$\frac{1}{r{2}^{}}$ kq₁*q₂

Hence, $\frac{F{12}^{}}{F{21}^{}}=\frac{1}{1}=1$ .