Question

${}_{89}A{c}^{227}$ is a member of actinium series. Another member of the same series is :

• A. ${}_{92}{U}^{235}$
• B. ${}_{90}T{h}^{232}$
• C. ${}_{89}A{c}^{225}$
• D. ${}_{15}{P}^{34}$
• E. ${}_{15}{P}^{217}$

Answer 1

The correct option is A ${}_{92}{U}^{235}$

${}_{89}A{c}^{227}$ is a member of actinium series. Another member of the same series is ${}_{92}{U}^{235}$.

Actinium series is $4n+3$ series. Here, remainder is three when the mass number is divided by four.

This series involves emission of 7 alpha and 4 beta particles.