$8 a^{3} + b^{3} + 12 a^{2} b + 6 a b^{2}$

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Solution

$We have 8 a^{3} + b^{3} + 12 a^{2} b + 6 a b^{2} = {(2 a)}^{3} + {(b)}^{3} + 6 a b (2 a + b) = {(2 a)}^{3} + {(b)}^{3} + 3 \times 2 a \times b (2 a + b) = {(2 a + b)}^{3} = (2 a + b) (2 a + b) (2 a + b)$

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Factorise: $8 a^{3} - b^{3} - 12 a^{2} b + 6 a b^{2}$

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8 a^{3} - b^{3} - 12 a^{2} b + 6 a b^{2}

8 a^{3} + b^{3} + 12 a^{2} b + 6 a b^{2}

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