8a³ − b³ − 4ax + 2bx

Open in App

Solution

The given expression to be factorized is

The given expression can be written as

Recall the formula for difference of two cubes

Using the above formula and taking common from the last two terms, we get

Take common. Then we have,

We cannot further factorize the expression.

So, the required factorization of is.

Suggest Corrections

Similar questions

Factorize $8 a^{3} - b^{3} - 4 a x + 2 b x$

8 a^{3} + b^{3} + 12 a^{2} b + 6 a b^{2}

Factorise: $8 a^{3} - b^{3} - 12 a^{2} b + 6 a b^{2}$

\frac{8 a^{3}}{27} - \frac{b^{3}}{8}

Join BYJU'S Learning Program