8g of a metal hydroxide on heating produces 5g of metal oxide. If the atomic mass of the metal is 7, the formula of its chloride is ?

$M C l_{3}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$M C l_{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$M C l$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$N o n e o f t h e s e$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$M C l$

$\frac{M a s s o f h y d r o x i d e}{E q u i v . m a s s o f h y d r o x i d e} = \frac{M a s s o f o x i d e}{E q u i v . m a s s o f o x i d e}$
or $\frac{8}{E_{M} + E_{E_{O H^{-}}}} (= \frac{8}{E_{M} + 17})$
$= \frac{5}{E_{M} + E_{O}} (= \frac{5}{E_{M} + 8}) \Rightarrow E_{M} = 7$
$V a l e n c y = \frac{A t o m i c m a s s}{E q u i v . m a s s} = \frac{7}{7} = 1;$
Hence metal chloride = MCl

Suggest Corrections

Similar questions

Q. The formula of a metal oxide is

M_{2} O_{3}

. If the metal forms its chloride, what will the formula of that compound be?

On being heated in oxygen 5.72 g of red metallic oxide A was converted to 6.36 g Black metallic oxide B. When 4.77 g of B was heated in a stream of H₂ gas, 3.81 g of metal M was formed. ( Atomic weight of metal is 63.50 g) Find

The formula of Red metallic oxide A .....

The formula if Black metallic oxide .....

The equivalent weight of metal M in B .....

Q. 3.80 gm of metal M is deposited at the cathode by passing 0.2 F of electricity through the solution of metal chlorides. The formula of the metal chloride is:
(atomic mass of M = 57 g/mol)

3 g

of an oxide of a metal is converted to chloride completely and it yielded

5 g

of chloride. Equivalent weight of the metal is

Q. Vapour density of a metal chloride is

66.

Its oxide contains

53 %

metal. The atomic weight of the metal is

Join BYJU'S Learning Program

8g of a metal hydroxide on heating produces 5g of metal oxide. If the atomic mass of the metal is 7, the formula of its chloride is ?

The correct option is C MCl Mass of hydroxideEquiv.mass of hydroxide=Mass of oxideEquiv.mass of oxide or 8EM+EEOH−(=8EM+17) =5EM+EO(=5EM+8)⇒EM=7 Valency=Atomic massEquiv.mass=77=1; Hence metal chloride = MCl