8th term of the series 2-2 - -2 - 0 - - will be -

Obviously the given series 2√(2) + √(2) + 0 + .... nbsp; nbsp;is an A.P. Here a = 2√(2), d = √(2). Hence 8th nbsp;term of the series = 2√(2) + (8 1) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

nth Term of an AP

8th term of t...

Question

8^th term of the series $2 \sqrt{2} + \sqrt{2} + 0 + . . . .$ will be ___.

- 5 \sqrt{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 \sqrt{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10 \sqrt{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 10 \sqrt{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $5 \sqrt{2}$
Obviously the given series $2 \sqrt{2} + \sqrt{2} + 0 + . . . .$ is an A.P. Here $a = 2 \sqrt{2}, d = - \sqrt{2} .$
Hence 8^th term of the series $= 2 \sqrt{2} + (8 - 1) (- \sqrt{2} = - 5 \sqrt{2} .$

Suggest Corrections

Similar questions

Q. 8^th term of the series

2 \sqrt{2} + \sqrt{2} + 0 + . . . .

will be ___.

8^{t h}

term of series

2 \sqrt{2} + \sqrt{2} + 0 + . . . . . .

will be

Q. In the series 2, 6, 18, 54, ...... what will be the 8th term?

Q. In the series

2, 6, 18, 54, . .,

what will be the

8^{t h}

term?

Q. In following question, a number series is given with one term missing. Choose the correct alternative that will same pattern and fill in the blank spaces.

In the Series 2, 6, 18, 54, , what will be the 8th term ?

Join BYJU'S Learning Program

8th term of the series 2√2+√2+0+.... will be ___.

The correct option is B 5√2Obviously the given series 2√2+√2+0+.... is an A.P. Here a=2√2,d=−√2. Hence 8th term of the series =2√2+(8−1)(−√2=−5√2.

8^th term of the series $2 \sqrt{2} + \sqrt{2} + 0 + . . . .$ will be ___.

The correct option is B $5 \sqrt{2}$
Obviously the given series $2 \sqrt{2} + \sqrt{2} + 0 + . . . .$ is an A.P. Here $a = 2 \sqrt{2}, d = - \sqrt{2} .$
Hence 8^th term of the series $= 2 \sqrt{2} + (8 - 1) (- \sqrt{2} = - 5 \sqrt{2} .$