The correct option is E 39^2 × 7^2 ÷√(441) 64 = 5^? ⇒ 81 × 49 ÷ 21 64 = 5^? ⇒ 3969 ÷ 21 64 = 5^? ⇒ 189 64 =5^? ⇒ 125 = 5^? ⇒ 5^3 = 5^? ∴ ? = 3 ...

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Byju's Answer

Standard XII

Mathematics

Cartesian Product

92× 72÷√441-6...

Question

$9^{2} \times 7^{2} \div \sqrt{441} - 64 = 5^{?}$

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Solution

The correct option is D 3
$9^{2} \times 7^{2} \div \sqrt{441} - 64 = 5^{?} \Rightarrow 81 \times 49 \div 21 - 64 = 5^{?} \Rightarrow 3969 \div 21 - 64 = 5^{?} \Rightarrow 189 - 64 = 5^{?} \Rightarrow 125 = 5^{?} \Rightarrow 5^{3} = 5^{?} ∴ ? = 3$

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Similar questions

$\frac{\sqrt{441}}{3} \times \frac{\sqrt{225}}{5} \times \frac{64}{\sqrt{256}} = ?$

Q. The number that least fits this set:
(324, 441, 97 and 64) is _________

$1^{2} + 3^{2} + 5^{2} + 7^{2} + 9^{2}$ =___.

$6^{2} + 7^{2} + 8^{2} + 9^{2} + 10^{2} =$ ___ .

Find the value of:

$(i) \frac{\sqrt{80}}{\sqrt{405}}$ $(i i) \frac{\sqrt{441}}{\sqrt{625}}$ $(i i i) \frac{\sqrt{1587}}{\sqrt{1728}}$ $(i v) \sqrt{72} \times \sqrt{338}$ $(v) \sqrt{45} \times \sqrt{20}$

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92×72÷√441−64=5?

The correct option is D 392×72÷√441−64=5?⇒81×49÷21−64=5?⇒3969÷21−64=5?⇒189−64=5?⇒125=5?⇒53=5?∴?=3

$9^{2} \times 7^{2} \div \sqrt{441} - 64 = 5^{?}$

The correct option is D 3
$9^{2} \times 7^{2} \div \sqrt{441} - 64 = 5^{?} \Rightarrow 81 \times 49 \div 21 - 64 = 5^{?} \Rightarrow 3969 \div 21 - 64 = 5^{?} \Rightarrow 189 - 64 = 5^{?} \Rightarrow 125 = 5^{?} \Rightarrow 5^{3} = 5^{?} ∴ ? = 3$