Question

$9$ balls are to be placed in $9$ boxes and $5$ of the balls cannot fit into $3$ small boxes. The number of ways of arranging one ball in each of the boxes is

• A. $18720$
• B. $18270$
• C. $17280$
• D. $12780$

Answer 1

The correct option is C $17280$

Required number of arrangements ${=}^6{P}_5\times 4!$
$=720\times 24$
$=17280$