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Aluminium

9. Calculate ...

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9. Calculate the freezing point of an aqueous solution of non-electrolyte having osmotic pressure of 2.0 atm at 300K. (Kf = 1.86 kg/mol , R = 0.0821 L atm/ K mol )

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Q. The freezing point of an aqueous solution of a non-electrolyte having an osmotic pressure

2.0

300

K_{f} = 1.86 K m o l^{- 1} k g

R = 0.08251 L a t m K^{- 1} m o l^{- 1}

), assuming molarity and molality are same is:

Q. An aqueous solution was found to have an osmotic pressure of 2.51 atm at

25^{o} C

. The freezing point of solution if

K_{f}

1.86 K m o l^{- 1} k g

Assume molarity and molality are same.

Q. An aqueous solution of urea has freezing point of

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. Assume molarity and molality by same.

K_{f}

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m o l^{- 1} k g

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Q. Osmotic pressure of a solution is 0.0821 atm at a temperature of 400 K. Calculate the concentration of solution in mol/litre.

[R = 0.0821 L a t m K^{- 1} m o l^{- 1}]

0.15 M

aqueous solution of

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exerts an osmotic pressure of

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310 K

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