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Question

9, cos' (-

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Solution

The inverse of a function f:AB exists if f is one-one onto i.e.,

y=f( x ) f 1 ( y )=x .

The given inverse trigonometry function is cos 1 ( 1 2 ) .

Let,

cos -1 ( 1 2 )=y

cosy= 1 2 =cos( π 4 ) =cos( π π 4 ) =cos( 3π 4 )

Since, the range of the principle value branch of cosec -1 is [ 0,π ] .

3π 4 [ 0,π ]

Thus, the principle value of cos -1 ( 1 2 ) is ( 3π 4 ) .


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