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Byju's Answer
Standard VII
Mathematics
Multiplication of Proper and Improper Fractions
9 1/2×2/7×7/1...
Question
9
1
2
×
2
7
×
7
19
×
1
5
equals
A
1
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B
1
2
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C
1
3
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D
1
5
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Solution
The correct option is
D
1
5
9
1
2
×
2
7
×
7
19
×
1
5
=
19
2
×
2
7
×
7
19
×
1
5
=
(
19
2
×
2
7
×
7
19
)
×
1
5
=
1
×
1
5
=
1
5
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0
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is equal to
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