-9 -10-2- - -9 -10-3- in usual form is given by- 9000-09-900-9900-099000-9

The correct option is A 9000.09 The usual forms of the expressions 9 ×10^ 2 and 9 ×10^3 are given by 0.09 and 9000. Thus, 9000 + 0.09 = 9000.09. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

(9 ×10^-2) + ...

Question

$(9 \times 10^{- 2}) + (9 \times 10^{3})$ in usual form is given by

9000.09

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

900.9

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9000.9

No worries! We‘ve got your back. Try BYJU‘S free classes today!

900.09

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
9000.09

The usual forms of the expressions $9 \times 10^{- 2}$ and $9 \times 10^{3}$ are given by 0.09 and 9000.
Thus, 9000 + 0.09 = 9000.09.

Suggest Corrections

Similar questions

Q. Question 2(iv)
Express the following numbers in usual form:

1.0001 \times 10^{9}

Write the numeral whose expanded form is given below:
(i) $6 \times 10^{4} + 3 \times 10^{3} + 0 \times 10^{2} + 7 \times 10^{1} + 8 \times 10^{0}$
(ii) $9 \times 10^{6} + 7 \times 10^{5} + 0 \times 10^{4} + 3 \times 10^{3} + 4 \times 10^{2} + 6 \times 10^{1} + 2 \times 10^{0}$
(iii) $8 \times 10^{5} + 6 \times 10^{4} + 4 \times 10^{3} + 2 \times 10^{2} + 9 \times 10^{1} + 6 \times 10^{0}$