$(9 \times \frac{1}{5}) + (9 \times 5) =$ __________.

$2 \times \frac{26}{5}$

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$9 \times \frac{26}{5}$

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$9 \times \frac{30}{5}$

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$2 \times \frac{16}{5}$

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Solution

The correct option is B
$9 \times \frac{26}{5}$

We know that, multiplying two numbers separately by 9 and then adding is same as multiplying the sum of two numbers by 9.

i.e., If $x$ and $y$ are any two numbers, then $9 x + 9 y = 9 (x + y)$

So, $(9 \times \frac{1}{5}) + (9 \times 5)$
$= 9 \times (\frac{1}{5} + 5)$
$= 9 \times \frac{26}{5}$

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Similar questions

(- \frac{8}{9} \times \frac{1}{- 5}) + (- \frac{8}{9} \times - \frac{- 7}{11}) = - \frac{8}{9} \times (\frac{1}{- 5} + \frac{- 7}{11})

Verify whether the given statement is true or false :

(i) $(\frac{5}{9} \div \frac{1}{3}) \div \frac{5}{2} = \frac{5}{9} \div (\frac{1}{3} \div \frac{5}{2})$

(ii) ${(- 16) \div \frac{6}{5}} \div \frac{- 9}{10} = (- 16) \div {\frac{6}{5} \div \frac{- 9}{10}}$

(iii) $(\frac{- 3}{5} \div \frac{- 12}{35}) \div \frac{1}{14} = \frac{- 3}{5} \div (\frac{- 12}{35} \div \frac{1}{14})$

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