90234Th disintegrates to give 82206Pb as the final product- The number of - and -particles are emitted during the process-

The correct option is A 7α and 6β The number of #160; #160; α and β particles are emitted during the process are #160; 7α and ...

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Standard VII

Chemistry

Sub-Atomic Particles

90234Th disin...

Question

$_{90}^{234} T h$ disintegrates to give $_{82}^{206} P b$ as the final product. The number of $α$ - and $β$ -particles are emitted during the process:

7 α

and

6 β

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7 α

and

5 β

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9 α

and

6 β

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None of these

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Solution

The correct option is A $7 α$ and $6 β$
The number of $α$ - and $β$ -particles are emitted during the process are $7 α$ and $6 β$ .

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Similar questions

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( b )

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(IIT-JEE, 2004)

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23490Th disintegrates to give 20682Pb as the final product. The number of α- and β-particles are emitted during the process:

The correct option is A 7α and 6βThe number of α- and β-particles are emitted during the process are 7α and 6β.

$_{90}^{234} T h$ disintegrates to give $_{82}^{206} P b$ as the final product. The number of $α$ - and $β$ -particles are emitted during the process:

The correct option is A $7 α$ and $6 β$
The number of $α$ - and $β$ -particles are emitted during the process are $7 α$ and $6 β$ .