90Th234 - 7- - 6- - ZXAIdentify ZXA-

195

You visited us 195 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Chemistry

Sub-Atomic Particles

90Th234 → 7α ...

Question

$_{90} T h^{234} \to 7 α + 6 β +_{Z} X^{A}$
Identify $_{Z} X^{A}$ .

_{84} P o^{206}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

_{92} U r^{238}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

_{82} P b^{206}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

_{83} B i^{208}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $_{82} P b^{206}$
On balancing the mass number and charge of the nuclear reaction, we get
$_{90} T h^{234} \to 7_{2} H e^{4} + 6_{_{- 1} e^{0}} +_{82} P b^{206}$
Hence, $_{Z} X^{A}$ is $_{82} P b^{206}$

Suggest Corrections

Similar questions

$T h^{234}$ disintegrates and emits 6β- and 7α-particles to form a stable element. Find the atomic number and mass number of the stable product. Also identify the element.
(IIT-JEE, 2004)

Q. ( a ) Calculate number of

α

and

β -

particles emitted when

_{92} U^{238}

changes into radioactive

_{82} P b^{206} .

( b )

T h^{234}

disintegrates and emits

6 β -

and

7 α -

particles to form a stable element. Find the atomic number and
mass number of the stable product. Also identify the element:

Q. The isotopes of an element X are

_{z} X^{A},_{z} X^{A + 1},_{z} X^{A + 2}

respectively. What is the ratio of the number of nucleons in these respective isotopes?

$T h^{234}$ disintegrates and emits 6β- and 7α-particles to form a stable element. Find the atomic number and mass number of the stable product. Also identify the element.
(IIT-JEE, 2004)

Q. On bombarding

_{7} N^{14}

with

α

-particles, the nuclei of the product formed after the release of a proton will be or In nuclear reaction

_{7} N^{14} +_{2} H e^{4} \to_{z} X^{A} +_{1} H^{1}

, the term

_{z} X^{A}

represents

Join BYJU'S Learning Program

90Th234→7α+6β+ZXAIdentify ZXA.

The correct option is C 82Pb206On balancing the mass number and charge of the nuclear reaction, we get90Th234→72He4+6−1e0+82Pb206Hence, ZXA is 82Pb206

$_{90} T h^{234} \to 7 α + 6 β +_{Z} X^{A}$
Identify $_{Z} X^{A}$ .

The correct option is C $_{82} P b^{206}$
On balancing the mass number and charge of the nuclear reaction, we get
$_{90} T h^{234} \to 7_{2} H e^{4} + 6_{_{- 1} e^{0}} +_{82} P b^{206}$
Hence, $_{Z} X^{A}$ is $_{82} P b^{206}$