Question

${}_{92}^{235}\text{U}{⟶}_{56}^{140}\text{Ba}{+}_{36}^{92}\text{Kr}+3{}_0^{1}n+E$

The number of neutrons and energy released in $n$ steps is :

• A. $3n,nE$
• B. $3^n,nE$
• C. $3^n,3^{n-1}E$
• D. none of these

Answer 1

The correct option is A $3n,nE$

From the above equation, we can see that in a single step, 3 neutrons (n) and 'E' amount energy are released.

Thus, for "n" no. of steps,

No. of neutrons released = (3+3+3+....n times) = 3n.

Amount of Energy released = (E+E+E+.....n times) = nE.

Hence, option A is correct.