$_{92} U^{235}$ + $_{0} n_{1}$ = $_{54} X e^{139}$ + $Y$ + $_{0} n^{1}$

Here $Y$ is

_{38} {Sr}^{95}

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_{38} {Si}^{95}

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_{38} {Ge}^{95}

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_{38} {Ni}^{95}

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Solution

The correct option is A $_{38} {Sr}^{95}$
On right hand side number of neutron emitted should be 2
$_{92}^{235} P +_{0}^{1} n \to_{54}^{139} X e +_{38}^{95} S r +_{0}^{1} n$

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