92 - 576 - 2 -1296-3-49

The correct option is C 9Here, 92 × 576 ÷ 2 √(1296) + (?)^3 + √(49) We can also write it as 92 × 576 ÷ 2 × 36 = (?)^3 + √(49) ⇒ 92 × 576 ÷ 72 = (?)^3 + √(49) H ...

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Byju's Answer

Standard XII

Physics

Vector Addition

92 × 576 ÷ 2 ...

Question

$92 \times 576 \div 2 \sqrt{1296} + (?)^{3} + \sqrt{49}$

3

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(9)^{2}

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9

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27

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N o n e o f t h e s e

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Solution

The correct option is C $9$
Here,
$92 \times 576 \div 2 \sqrt{1296} + (?)^{3} + \sqrt{49}$
We can also write it as
$92 \times 576 \div 2 \times 36 = (?)^{3} + \sqrt{49}$
$\Rightarrow 92 \times 576 \div 72 = (?)^{3} + \sqrt{49}$
Here, we apply the BODMAS rule.
$S o, 92 \times 8 = (?)^{3} + 7 \Rightarrow 736 - 7 = (?)^{3} \Rightarrow (?) = \sqrt[3]{729} = 9$

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92×576÷2√1296+(?)3+√49

The correct option is C 9Here, 92×576÷2√1296+(?)3+√49 We can also write it as 92×576÷2×36=(?)3+√49 ⇒92×576÷72=(?)3+√49 Here, we apply the BODMAS rule. So,92×8=(?)3+7⇒736−7=(?)3⇒(?)=3√729=9

$92 \times 576 \div 2 \sqrt{1296} + (?)^{3} + \sqrt{49}$