$_{92} U^{235}$ disintegrates and emits $4 β$ - and $7 α$ - particles to form a stable element. Find the atomic number and mass number of the stable product. Also identify the element.

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Solution

$_{92} U^{235}$ emits $4 β$ and $7 α$

After Emission of $4 β$ particles (4 $_{- 1} e^{0}$ particles) ,the Atomic and the Mass number becomes 96 and 235.

After Emission of $7 α$ particles (7 $_{2} H e^{4}$ particles) ,the Atomic and the Mass number becomes 82 and 207 respectively.

The Element is Lead.

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92U235 disintegrates and emits 4β - and 7α - particles to form a stable element. Find the atomic number and mass number of the stable product. Also identify the element.

92U235 emits 4β and 7αAfter Emission of 4β particles (4 −1e0 particles) ,the Atomic and the Mass number becomes 96 and 235.After Emission of 7α particles (7 2He4 particles) ,the Atomic and the Mass number becomes 82 and 207 respectively.The Element is Lead.

$_{92} U^{235}$ disintegrates and emits $4 β$ - and $7 α$ - particles to form a stable element. Find the atomic number and mass number of the stable product. Also identify the element.