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Byju's Answer
Standard IX
Mathematics
Algebraic Identities
92U238→ 56Ba1...
Question
92
U
238
→
56
B
a
143
+
−
−
−
−
−
−
−
−
+
0
n
1
Open in App
Solution
92
U
238
→
56
B
a
143
+
36
K
r
94
+
0
n
1
Suggest Corrections
0
Similar questions
Q.
92
U
238
decays to a stable nucleus of
82
P
b
206
. In this process:
Q.
On analysis, a sample of uranium ore was found to contain
0.277
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and
1.667
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Q.
How many
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particles are emitted when
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238
disintegrates to form lead
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P
b
206
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Q.
As a result of radioactive disintegration the nucleus
92
U
238
converts into
91
P
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234
. The particles emitted during the process are
Q.
If by successive disintegration of
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U
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, the final product obtained is
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