Question

$(96{)}^2-1$ is a product of two consecutive odd numbers. Find those two odd numbers.

• A. 96 and 98
• B. 93 and 95
• C. 95 and 97
• D. 99 and 101

Answer 1

The correct option is C 95 and 97

$(96{)}^2-1=9215$
We can express the above number into general form $a^2-1=(a+1)\times (a-1)$
Where a = 96
So, $(96{)}^2-1=(96+1)\times (96-1)$
= $97\times 95=9215$
Therefore, the two odd consecutive numbers are 95 and 97.