Question

$96,000C$ deposit on 1 gm atom of mono-valent silver. The positive charge on a silver ion is equal in magnitude to that of an electron and Avogadro's number is $6\times {10}^{23}$. Electronic charge will be:

• A. $-1.6\times {10}^{-19}C$
• B. $5.76\times {10}^{28}C$
• C. $-6.2\times {10}^{18}C$
• D. $-160C$

Answer 1

The correct option is A $-1.6\times {10}^{-19}C$

One gm atom of silver will include $N_A$ particles or electron

We know that: $Q=N_A\times e$
Given, $Q=96000C$ and $N_A=6\times {10}^{23}$
So, $e=\frac{Q}{N_A}$$=\frac{96000}{6\times {10}^{23}}$$=16000\times {10}^{-23}$ $=1.6\times {10}^{-19}C$