9648 is divisible by both 6 and 8.
9638
If a number is divisible by both 2 and 3, then it will be divisible by 6.
And a number will be divisible by 8 only if the last three digits are divisible by 8.
For 9648, it is divisible by both 2 as the last digit is even.
it is divisible 3 as the sum if the digits = 9 + 6 + 4 + 8 = 27 is divisible by 3.
9648 is divisible by 8 as the last three digits (648) are divisible by 8.
Hence, 9648 is divisible by 6 and 8.