9650 charge is passed through an aqueous solution of metal nitrate M(NO $_{3}$ ) $_{x}$ to obtain 2 g metal (at. mass 180). What is the valence of metal?

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Solution

The correct option is B 9
2 g metal corresponds to $\frac{2}{180} = 0.0111$ moles.
If n is the valency of metal, then 0.0111 moles of metal will b obtained by 0.0111n faraday of charge. But this is equal to $\frac{9650}{96500} = 0.1$ faraday.
Hence, $0.0111 n = 0.1$
$n = 9$
Hence, the valence of metal is 9.

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9650 charge is passed through an aqueous solution of metal nitrate M(NO3)x to obtain 2 g metal (at. mass 180). What is the valence of metal?

The correct option is B 92 g metal corresponds to 2180=0.0111 moles.If n is the valency of metal, then 0.0111 moles of metal will b obtained by 0.0111n faraday of charge. But this is equal to 965096500=0.1 faraday.Hence, 0.0111n=0.1n=9Hence, the valence of metal is 9.

9650 charge is passed through an aqueous solution of metal nitrate M(NO $_{3}$ ) $_{x}$ to obtain 2 g metal (at. mass 180). What is the valence of metal?