Question

$98g$ of an acid on treatment with an excess of an alkali forms salt along with $36g$ of water. What is the equivalent mass of the acid?

• A. $98.0g/equivalent$
• B. $49.0g/equivalent$
• C. $24.5g/equivalent$
• D. $73.5g/equivalent$

Answer 1

The correct option is B $49.0g/equivalent$

$\frac{36}{18}=2$ moles or equivalents of water are produced. (n-factor =1)

For this, $2$ equivalents of acid should react.
Thus, $\frac{W_{acid}}{E_{acid}}=2$
Hence, the equivalent weight of acid $\left(E_{acid}\right)=49$ g/equivalent.