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Byju's Answer
Standard VIII
Mathematics
Expansion of (x^2 - y^2)
9992
Question
(999)³
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Solution
(999)^3
= (1000 - 1)^3
(now we can solve by the identity (a-b)^3=a^3 - 3a^2b + 3ab^2 - b^3 )
= (1000)^3 + 3(1000)^2 * (-1) + 3*1000*(-1)^2 + (-1)^3
= 1000000000 - 3000000 + 3000 - 1
= 997002999.
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