CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Expansion of (a ± b ± c)²

9993

Question

$(999)^{3}$

A

996002999

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

997002999

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

99800299

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

None of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $997002999$
$(1000 - 1)^{3}$
$= (1000)^{3} - (1)^{3} - 3 (1000) (999)$
$= 997002999$

Suggest Corrections

thumbs-up

0

Similar questions

(999)^{3}

Q. Evaluate:
(i) (95)³
(ii) (999)³

Q. Evaluate the following using suitable identities

(999)^{3}

Q. Use the binomial theorem to find

999^{3}

Q. Evaluate each of the following using suitable identities.
(1)

(104)^{3}

(999)^{3}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

(a ± b ± c)²

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Expansion of (a ± b ± c)²

Standard IX Mathematics

Join BYJU'S Learning Program

CrossIcon