Question

$999\frac{1}{7}+999\frac{2}{7}+999\frac{3}{7}+999\frac{4}{7}+999\frac{5}{7}+999\frac{6}{7}=$?

• A. $2997$
• B. $5997$
• C. $5979$
• D. $5994$

Answer 1

The correct option is A $2997$

$999\frac{1}{7}+999\frac{2}{7}+999\frac{3}{7}+999\frac{4}{7}+999\frac{5}{7}+999\frac{6}{7}=$

$s_n=\frac{n}{2}[a+l]$

where $s_n=$sum of $n$ terms

$n=$no. of terms

$a=$first term

$l=$last term

$=\frac{6}{2}[999\frac{1}{7}+999\frac{6}{7}]$

$=999\times 3$

$=2997$