We solve by using the formula #160; (a + b)^2 = a^2 + b^2 + 2abWe get, #160; ⇒(3m)^2 +(4)^2+2 (3a)(4)=(3m+4)^2 ...

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9m2+24m+16

Question

$9 m^{2} + 24 m + 16$

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Solution

We solve by using the formula $(a + b)^{2} = a^{2} + b^{2} +$ 2ab
We get,
$\Rightarrow (3 m)^{2} + (4)^{2} + 2 (3 a) (4) = (3 m + 4)^{2}$

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$9 m^{2} + 24 m + 16$

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