The correct option is A 9xFactorising the dividend 9x^2 + 18, we get, 9x^2 + 18 = (3×3×x×x) + (2×3×3×x) =(x +2)×9x ∴ [9x^2 + 18x]÷(x+2) = [(x +2)×9x]÷(x+2) = 9 ...

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Standard VIII

Mathematics

Factorisation

[9 x2+18 x] ÷...

Question

$[9 x^{2}$ + 18x] $\div (x + 2)$

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18x

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(x^{2} + 2)

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Solution

The correct option is A 9x
Factorising the dividend $9 x^{2}$ + 18, we get,
$9 x^{2}$ + 18 = $(3 \times 3 \times x \times x) + (2 \times 3 \times 3 \times x)$
= $(x + 2) \times 9 x$
$∴$ $[9 x^{2}$ + 18x] $\div (x + 2)$ = $[(x + 2) \times 9 x] \div (x + 2)$ = 9x

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[9x2 + 18x]÷(x+2)

The correct option is A 9xFactorising the dividend 9x2 + 18, we get, 9x2 + 18 = (3×3×x×x)+(2×3×3×x) =(x+2)×9x ∴ [9x2 + 18x]÷(x+2) = [(x+2)×9x]÷(x+2) = 9x

$[9 x^{2}$ + 18x] $\div (x + 2)$

The correct option is A 9x
Factorising the dividend $9 x^{2}$ + 18, we get,
$9 x^{2}$ + 18 = $(3 \times 3 \times x \times x) + (2 \times 3 \times 3 \times x)$
= $(x + 2) \times 9 x$
$∴$ $[9 x^{2}$ + 18x] $\div (x + 2)$ = $[(x + 2) \times 9 x] \div (x + 2)$ = 9x